BCECE Engineering BCECE Engineering Solved Paper-2011

  • question_answer
    A radio transmitter operates at a frequency of 880 kHz and power of 10 kW. The number of photons emitted per second is

    A)  \[13.27\,\times {{10}^{4}}\]

    B)  \[13.27\,\times {{10}^{34}}\]

    C)  \[1327\,\times {{10}^{34}}\]     

    D)                         \[1.71\times {{10}^{31}}\]

    Correct Answer: D

    Solution :

    Number of photons emitted per second \[=\frac{Power}{hv}=\frac{10\times {{10}^{3}}}{6.6\times {{10}^{-34}}\times 880\times {{10}^{3}}}\] \[=1.71\times {{10}^{31}}\]


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