A) 3.77 J
B) 1.885 J
C) \[0.95\times {{10}^{-3}}J\]
D) \[1.9\times {{10}^{-3}}J\]
Correct Answer: D
Solution :
Work done \[W=8\pi {{R}^{2}}T\] \[=8\times 3.14{{(5\times {{10}^{-2}})}^{2}}\times 0.03\] \[=1.9\times {{10}^{-3}}\,J\]
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