A) 1.5
B) 2.0
C) 1.0025
D) 3.5
Correct Answer: C
Solution :
\[{{q}_{0}}={{C}_{0}}{{V}_{0}}\] and \[q=C{{V}_{0}}\] \[\therefore \] \[\Delta q=q-{{q}_{0}}=(C-{{C}_{0}}){{V}_{0}}\] or \[\Delta q=({{\varepsilon }_{r}}{{C}_{0}}-{{C}_{0}}){{V}_{0}}\] or \[\Delta q=({{\varepsilon }_{r}}-1){{C}_{0}}{{V}_{0}}\] ?(i) Here, \[\Delta q=7.5\times {{10}^{-4}}C\] \[{{C}_{0}}=6\times {{10}^{-4}}F\] and \[{{V}_{0}}=500\,V\] Putting the values in Eq.(i), we get \[{{\varepsilon }_{r}}=1.0025\]
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