BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    A solenoid is 1.5 m long and its inner diameter is 4.0 cm. It has 3 layers of windings of 1000 turns each and carries a current of 2.0A. The magnetic flux for a cross-section of the solenoid is nearly

    A)  \[4.1\,\times {{10}^{-5}}Wb\]                   

    B)         \[5.2\,\times {{10}^{-5}}Wb\]

    C)         \[6.31\,\times {{10}^{-31}}Wb\]              

    D)         \[2.5\,\times {{10}^{-7}}Wb\]

    Correct Answer: C

    Solution :

    Magnetic flux is a measure of the quantity of magnetism, taking account of the strength and extent of magnetic field.                 \[\phi =nBA\] where n is number of turns, B is magnetic field and A is area. Given, \[n=1000,i=2A,r=2\times {{10}^{-2}}m,\] \[l=1.5\,m\] Also magnetic field B of a solenoid of length \[l\] is \[B=\frac{{{\mu }_{0}}ni}{l}\]                 \[\therefore \]  \[\phi \text{=}\frac{{{\mu }_{0}}{{n}^{2}}iA}{l}\]                                                                                                                                                                                                                                                               \[=\frac{3\times {{10}^{-7}}\times 4\pi \times {{(1000)}^{2}}\times 2\times \pi {{(2\times {{10}^{-2}})}^{2}}}{1.5}\]                                 \[\phi \text{= 6}\text{.31}\times {{10}^{-3}}\,Wb\]


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