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BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    The ratio of molecular masses of two radioactive substances is 3/2 and the ratio of their decay constants is 4/3, Then, the ratio of their initial activities per mole will be

    A)  2                                            

    B)  4/3

    C)  8/9                       

    D)         9/8

    Correct Answer: B

    Solution :

    Activity,\[A=\frac{-dN}{dt}=\lambda N\] As the number of nucleic (N) per mole are equal for both the substances, irrespective of their molecular mass therefore, \[A\propto \lambda \] \[\frac{{{A}_{1}}}{{{A}_{2}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}=\frac{4}{3}\]


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