BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    Two resistors 400\[\Omega \] and 800\[\Omega \]are connected in series with a 6 V battery- The potential difference measured by voltmeter of 10\[k\Omega \] across \[400\,\Omega \] resistor is

    A)  2 V                                        

    B)  1.95 V

    C)  3.8 V                    

    D)         4 V

    Correct Answer: B

    Solution :

    Here, the resistances of \[400\,\Omega \] and \[10000\,\Omega \]are in parallel, their effective resistance \[{{R}_{P}}\]will be \[{{R}_{P}}=\frac{400\times 10000}{400+10000}\] \[=\frac{5000}{13}\Omega \] Total resistance of the circuit, \[=\frac{5000}{13}+800=\frac{15400}{13}\Omega \] Current in the circuit \[i=\frac{6}{15400/13}=\frac{39}{7700}A\] Potential difference across voltmeter \[=i{{R}_{P}}\]   \[=\frac{39}{7700}\times \frac{5000}{13}=1.95\,V\]


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