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BCECE Engineering BCECE Engineering Solved Paper-2010

  • question_answer
    Nitrogen \[({{N}_{2}})\] is in equilibrium state at T = 421 K. The value of most probable speed, \[{{v}_{mp}}\]is

    A)  400 m/s       

    B)                        421 m/s

    C)  500 m/s              

    D)         600 m/s

    Correct Answer: C

    Solution :

    Most probable velocity, \[{{v}_{mp}}=\sqrt{\frac{2kT}{m}}\] \[=\sqrt{\frac{2RT}{m}}=\sqrt{\frac{2\times 8.31\times 421}{28\times {{10}^{-3}}}}\] \[=499.89=500\,m/s\]


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