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BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    A line is drawn through the point P(3,11) to cut  the circle \[{{x}^{2}}+{{y}^{2}}=9\]at A and B. Then, \[PA.PB\]is equal to

    A)  9                            

    B)         121                       

    C)  205                       

    D)         139

    Correct Answer: B

    Solution :

    Let \[{{S}_{1}}={{x}^{2}}+{{y}^{2}}=9\] \[PA.PB={{(\sqrt{{{S}_{1}}})}^{2}}\] \[={{\left( \sqrt{{{(3)}^{3}}+{{(11)}^{2}}-9} \right)}^{2}}=121\]


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