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BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    If the system of equations \[ax+y=3,\]\[x+2y=3,3x+4y=7\]is consistent, then value of a is equal to

    A)  2                            

    B)         1                            

    C)         -1                          

    D)         0

    Correct Answer: A

    Solution :

    The intersection point of \[x+2y=3\]and \[3x+4y=7\]is \[(1,1).\] For consistent, point\[(1,1)\]satisfies the equation \[ax+y=3\]                 \[\therefore \]  \[a+1=3\]                 \[\Rightarrow \]               \[a=2\]


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