A) an ellipse
B) a parabola
C) a circle
D) _ a straight line through point \[\bar{a}\]
Correct Answer: C
Solution :
Given, \[\bar{z}=\bar{a}+\frac{{{r}^{2}}}{z-a},r>0\] \[\Rightarrow \]\[\bar{z}(z-a)=\bar{a}(z-a)+{{r}^{2}}\] \[\Rightarrow \]\[z\bar{z}-a\bar{z}-\bar{a}z+a\bar{a}+{{r}^{2}}=0\] This represents the equation of a circle.
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