A) \[{{\text{K}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\]is fairly soluble in water
B) it has no water of crystallization
C) \[\text{KHC}{{\text{O}}_{\text{3}}}\] is highly soluble in water
D) \[{{\text{K}}_{\text{2}}}\text{C}{{\text{O}}_{\text{3}}}\]decomposes in \[{{\text{H}}_{\text{2}}}\text{O}\]
Correct Answer: C
Solution :
Solvay-ammonia process involves the formation of bicarbonate and bicarbonate of potassium, ie, \[KHC{{O}_{3}},\]is highly soluble in water. Thats why \[{{K}_{2}}C{{O}_{3}}\]cannot be prepared by Solvay-ammonia process.
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