A) liberating \[C{{O}_{2}}\]
B) hydration
C) dehydration
D) changing into \[CaC{{O}_{3}}\]
Correct Answer: B
Solution :
When water is added to plaster of Paris, a substance, called gypsum that becomes hard; is formed. Thus, plaster of Paris is hardened by hydration. \[\underset{\text{plaster}\,\text{of}\,\text{paris}}{\mathop{CaS{{O}_{4}}.\frac{1}{2}{{H}_{2}}O+1\frac{1}{2}{{H}_{2}}O}}\,\xrightarrow{{}}\underset{\begin{smallmatrix} \text{gypsum} \\ \text{(hard)} \end{smallmatrix}}{\mathop{CaS{{O}_{4}}.2{{H}_{2}}O}}\,\]
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