BCECE Engineering BCECE Engineering Solved Paper-2009

  • question_answer
    W. For  the  reaction,   \[2B+AC,\]   the equilibrium constant is

    A) \[\frac{[A]{{[B]}^{3}}}{[C]}\]      

    B)         \[\frac{[C]}{[A][2B]}\]  

    C)         \[\frac{[C]}{[A]{{[B]}^{2}}}\]     

    D)         \[\frac{[A][B]}{[C]}\]

    Correct Answer: C

    Solution :

    For the reaction, \[2B+AC\] Rate of forward reaction\[={{k}_{f}}[A]{{[B]}^{2}}\] Rate of backward reaction \[={{k}_{b}}[C]\] At equilibrium, Rate of forward reaction = Rate of backward reaction \[{{k}_{f}}[A]{{[B]}^{2}}={{k}_{b}}[C]\] \[\frac{{{k}_{f}}}{{{k}_{b}}}=\frac{[C]}{[A][B]}={{K}_{c}}\]


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