A) \[6\times {{10}^{23}}\]atoms of C
B) \[6\times {{10}^{23}}\]atoms of O
C) \[18\times {{10}^{23}}\]molecules of \[C{{O}_{2}}\]
D) 3 g-atoms of \[C{{O}_{2}}\]
Correct Answer: A
Solution :
1 mole of \[C{{O}_{2}}=6\times {{10}^{23}}\]atoms of C \[=2\times 6\times {{10}^{23}}\]atoms of O \[=6\times {{10}^{23}}\]molecules of \[C{{O}_{2}}\] = 44 g-atoms of \[C{{O}_{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
