A) 1.2, 1.6
B) 1.8, 1.0
C) 0.4, 2.4
D) 0.8, 2.0
Correct Answer: A
Solution :
\[\begin{align} & {{H}_{2}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{I}_{2}}\,\,\,\,\,\,\,\,\rightleftharpoons \,\,\,\,\,\,\,\,\,\,\,2HI \\ & Initially\,\,\,\,\,\,\,1\,mol\,\,\,\,\,\,\,\,\,\,\,\,\,\,2\,mol\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2\,mol \\ & at\,eq.\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0.2\,mol\,\,\,\,\,\,\,\,2-0.8\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2\times 0.8 \\ & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,=\,1.2\,mol\,\,\,\,\,\,\,\,\,\,\,=1.6\,mol \\ \end{align}\] Amount of \[{{H}_{2}}\](and hence\[{{I}_{2}}\]) consumed \[=1-0.2=0.8\]You need to login to perform this action.
You will be redirected in
3 sec