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BCECE Engineering BCECE Engineering Solved Paper-2008

  • question_answer
    The value of \[\Lambda _{eq}^{\infty }\] for\[N{{H}_{4}}Cl,NaOH\] and\[NaCl\] are respectively, 149.74, 248.1 and \[126.4\,oh{{m}^{-1}}\,c{{m}^{2}}e{{q}^{-1}}.\] The value of \[A_{eq}^{\infty }\]of \[N{{H}_{4}}OH\]is

    A) 371.44  

    B)        271.44              

    C) 71.44

    D) Cannot be predicted from given data

    Correct Answer: B

    Solution :

    \[\Lambda _{eq}^{\infty }(N{{H}_{4}}OH)=\Lambda _{eq}^{\infty }(N{{H}_{4}}Cl)+\Lambda _{eq}^{\infty }(NaOH)\] \[-\Lambda _{eq}^{\infty }(NaCl)\] \[=(149.74+248.1-126.4)\] \[=271.44\,{{\Omega }^{-1}}c{{m}^{2}}e{{q}^{-1}}\]


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