A) reducing agent
B) acidic
C) oxidizing agent
D) None of the above
Correct Answer: C
Solution :
\[{{H}_{2}}S\]acts as a reducing agent, because it can reduce PbO into PbS. \[PbO+{{H}_{2}}S\xrightarrow{{}}PbS+{{H}_{2}}O\] (b) It is acidic in nature. In calcogens, the acidic nature of hydride increases from \[{{H}_{2}}O\]to \[{{H}_{2}}\,Te.\] (c) It is not an oxidizing agent.
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