A) \[BeC{{l}_{2}},\text{ }s{{p}^{2}},\,\]linear
B) \[BeC{{l}_{2}},\text{ }s{{p}^{2}},\]triangular planar
C) \[~BC{{l}_{3}},\text{ }s{{p}^{2}},\] triangular planar
D) \[BC{{l}_{3}},s{{p}^{3}},\]tetrahedral
Correct Answer: C
Solution :
\[BeC{{l}_{2}}\]has only two bond pair of electrons. So, its hybridisation is sp and bond angle is \[{{180}^{o}}.\] Its geometry is linear. In \[B{{C}_{3}},\]there is three bond pairs of electrons. So, its hybridisation is \[s{{p}^{2}}\]and bond angle is \[{{120}^{o}}.\] Its geometry is trigonal planar.
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