question_answer

Aniline is prepared in presence of Fe/HCl from

A) benzene             

B) nitrobenzene

C)                        dinitrobenzene

D)        None of these

Correct Answer: B

Solution :

Key Idea Aniline is prepared by the reduction of nitrobenzene in acidic medium. Mechanism \[3Fe+6HCl\xrightarrow{{}}3FeC{{l}_{2}}+6H\] \[{{C}_{6}}{{H}_{5}}N{{O}_{2}}+6H\xrightarrow{{}}{{C}_{6}}{{H}_{5}}N{{H}_{2}}+2{{H}_{2}}O\] \[FeC{{l}_{2}}+2{{H}_{2}}O\xrightarrow{{}}Fe{{(OH)}_{2}}+2HCl\] So, \[{{C}_{6}}{{H}_{5}}N{{O}_{2}}+2Fe{{(OH)}_{2}}+4{{H}_{2}}O\xrightarrow{{}}\] \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}+Fe{{(OH)}_{3}}\]