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BCECE Engineering BCECE Engineering Solved Paper-2007

  • question_answer
    Number of divisiors of the form \[(4n+2),n\ge 0\] of the integer 240 is

    A)  4                            

    B)         8                            

    C)  10                         

    D)         3

    Correct Answer: A

    Solution :

    \[\because \]     \[240={{2}^{4}}.3.5\] \[\therefore \] Total number of divisors \[=(4+1)\,(2)\,(2)=20\] Out of these 2, 6, 10 and 30 are of the form \[4n+2.\]


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