A) no solution
B) unique solution
C) infinite number of solution
D) none of the above
Correct Answer: B
Solution :
We have \[{{\sin }^{-1}}x-{{\cos }^{-1}}x={{\cos }^{-1}}\frac{\sqrt{3}}{2}\] \[\Rightarrow \] \[{{\sin }^{-1}}x-co{{s}^{-1}}x=\frac{\pi }{6}\] But \[{{\sin }^{-1}}x+{{\cos }^{-1}}x=\frac{\pi }{2}\] Therefore \[{{\sin }^{-1}}x=\frac{\pi }{3}\]and \[{{\cos }^{-1}}x=\frac{\pi }{6}\] \[\Rightarrow \]\[x=\frac{\sqrt{3}}{2}\]is the unique solution.
You need to login to perform this action.
You will be redirected in
3 sec
