A) 4
B) 3
C) 12
D) 6
Correct Answer: A
Solution :
We have, \[{{T}_{2}}=14{{a}^{5/2}}\] \[\Rightarrow \]\[{{\,}^{n}}{{C}_{1}}{{({{\alpha }^{1/13}})}^{n-1}}{{({{a}^{3/2}})}^{1}}=14{{a}^{5/2}}\] \[\Rightarrow \] \[n{{a}^{\frac{n-1}{13}+\frac{3}{2}}}=14{{a}^{5/2}}\] \[\Rightarrow \] \[n=14\] \[\therefore \] \[\frac{{{\,}^{n}}{{C}_{3}}}{{{\,}^{n}}{{C}_{2}}}=\frac{{{\,}^{14}}{{C}_{3}}}{{{\,}^{14}}{{C}_{2}}}=\frac{12}{3}=4.\]You need to login to perform this action.
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