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BCECE Engineering BCECE Engineering Solved Paper-2007

  • question_answer
    For a party 8 guests are invited by a husband and his wife. They sit in a row for dinner. The probability that the husband and his wife sit  together is

    A) \[\frac{2}{7}\]                   

    B)         \[\frac{2}{9}\]                  

    C)  \[\frac{1}{9}\]                  

    D)         \[\frac{4}{9}\]

    Correct Answer: B

    Solution :

    Total number of way of sitting \[=9!\] and number of favourable ways of sitting \[=2\times 8!\] \[\therefore \] Required probability \[=\frac{2\times 8!}{9!}=\frac{2}{9}.\]


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