A) \[x+y+z=9\]
B) \[x+y+z=-9\]
C) \[2x+3y+4z=9\]
D) \[2x+3y+4z=-9\]
Correct Answer: A
Solution :
The DRs of the joining of the points (1, 2, 3) (3, 4, 5) are \[(3-1,4-2,5-3),\]i.e., \[(2,2,2)\]Also the mid point of the join of the points \[(1,2,3)\] and \[(3,4,5)\]is \[(2,3,4).\] \[\therefore \] Equation of plane which passes through \[(2,3,4)\] and the D.Rs of its normal are \[(2,2,2)\]is \[2(x-2)+2(y-3)+2(z-4)=0\] \[\Rightarrow \] \[x+y+z-9=0\] \[\Rightarrow \] \[x+y+z=9.\] Note: If any line is perpendicular to the plane then the plane.
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