A) \[{{C}_{6}}{{H}_{5}}-N=N-{{C}_{6}}{{H}_{5}}\]
B) \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}\]
C) \[{{C}_{6}}{{H}_{5}}NO\]
D) \[{{C}_{6}}{{H}_{5}}NHOH\]
Correct Answer: D
Solution :
Key Idea: When nitrobenzene is reduced with a neutral reducing agent (Zn dust \[-N{{H}_{4}}Cl.Al-Hg\]couple and water etc), phenyl hydroxylamine is formed. \[{{C}_{5}}{{H}_{5}}N{{O}_{2}}+2[H]\xrightarrow[+N{{H}_{4}}Cl-{{H}_{2}}O]{Zn\,dust}\] \[\underset{\text{Nitrosobenzene}}{\mathop{{{C}_{6}}{{H}_{5}}NO}}\,\xrightarrow{2[H]}\underset{\begin{smallmatrix} \text{Phenyl}\,\text{hydroxyl} \\ \,\,\,\,\,\,\text{amine} \end{smallmatrix}}{\mathop{{{C}_{6}}{{H}_{5}}NHOH}}\,\]
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