BCECE Engineering BCECE Engineering Solved Paper-2007

  • question_answer
    In a common-base circuit of a transistor current amplification factor is 0.95. The base current when emitter current is 2 mA, will be

    A)  0.2mA                                 

    B)  0.1mA                 

    C)  0.002 mA           

    D)         none of these

    Correct Answer: B

    Solution :

    Key Idea: Current amplification factor or current gain is just the ratio of collector current to emitter current. In a common-base configuration of a transistor circuit                 \[\text{Current}\,\text{gain,}\,\alpha =\frac{\text{collecter}\,\text{current}}{\text{emitter}\,\text{current}}=\frac{{{i}_{C}}}{{{i}_{g}}}\]                 \[\Rightarrow \]               \[{{i}_{c}}=0.95\times 2\times {{10}^{-3}}A=1.9\,mA\] Also emitter current is sum of base current and collector current Also, \[{{i}_{B}}={{I}_{E}}-{{i}_{C}}=2-1.9=1.9\,mA\] Note: Base current is very less than emitter current.


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