A) \[325{{\,}^{o}}C\]
B) 325 K
C) \[~39{{\,}^{o}}C\]
D) \[320{{\,}^{o}}C\]
Correct Answer: C
Solution :
For a refrigerator coefficient of performance (COP) is defined as the ratio of the amount of heat removed at the lower temperature to the work put into the system (i.e., the engine) \[COP=\frac{{{Q}_{low}}}{W}=\frac{{{T}_{low}}}{{{T}_{high}}-{{T}_{low}}}\] Given, \[{{T}_{low}}=273-13=260\,K,COP=5\] \[\Rightarrow \] \[5=\frac{260}{{{T}_{H}}-260}\] \[\Rightarrow \] \[5{{T}_{H}}-1300=260\] \[\Rightarrow \] \[{{T}_{H}}=312\,K\] \[\Rightarrow \] \[{{T}_{H}}=312\,-273=39{{\,}^{o}}C\]
You need to login to perform this action.
You will be redirected in
3 sec
