question_answer

In the equation \[{{H}_{2}}S+2HN{{O}_{3}}\xrightarrow{{}}2{{H}_{2}}O+2N{{O}_{2}}+S.\]The equivalent weight of hydrogen sulphide is:

A)  18                                         

B)  68

C)  34                         

D)         17

Correct Answer: D

Solution :

\[{{H}_{2}}S+2HN{{O}_{3}}\xrightarrow{{}}2{{H}_{2}}O+2N{{O}_{2}}+S\] Hence, the equivalent weight of \[{{H}_{2}}S=\frac{\text{mlecular}\,\text{weight}}{\text{change}\,\text{in}\,\text{oxidation}\,\text{number}}=\frac{34}{2}=17\]