A) 9.6 kg
B) 96.0 kg
C) 6.4 kg
D) 2.8 kg
Correct Answer: A
Solution :
\[\underset{12\,\times \,2\,+\,4\,=\,28}{\mathop{{{C}_{2}}{{H}_{4}}}}\,+\underset{96}{\mathop{3{{O}_{2}}}}\,\xrightarrow{{}}2C{{O}_{2}}+2{{H}_{2}}O\] \[\because \]The weight of oxygen required for complete combustion of 28 g ethylene =96 g. \[\therefore \] Weight of oxygen required for combustion of 2.8 kg ethylene \[=\frac{96\times 2.8\times 1000}{28\times 1000}kg=9.8\,kg\]
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