question_answer

If boiling point of water is \[95{}^\circ F\], what will be reduction at Celsius scale?

A) \[7{}^\circ C\]                                   

B)        \[65{}^\circ C\]

C)        \[63{}^\circ C\]                                 

D)        \[35{}^\circ C\]

Correct Answer: D

Solution :

The relation between Celsius scale and Fahrenheit scale is as derived below: 100 parts of Celsius scale = 180 parts of Fahrenheit scale \[\therefore \]1 part of Celsius scale \[=\frac{9}{5}\] parts of Fahrenheit scale Hence, \[{{T}_{F}}=32+\frac{9}{5}{{T}_{C}}\] or            \[{{T}_{C}}=\frac{5}{9}({{T}_{F}}-32)\] Given,   \[{{T}_{F}}={{95}^{o}}F\] \[\therefore \]                  \[{{T}_{C}}=\frac{5}{9}(95-32)\]                                 \[=35{{\,}^{o}}C\]