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BCECE Engineering BCECE Engineering Solved Paper-2006

  • question_answer
    Youngs modulus of the material of a wire is V. On pulling the wire by a force F, the increase in its length is x. The potential energy of the stretched wire is:

    A)  \[\frac{1}{2}Fx\]                             

    B)         \[\frac{1}{2}Yx\]

    C)         \[\frac{1}{2}F{{x}^{2}}\]                              

    D)         none of these

    Correct Answer: A

    Solution :

    The potential energy of the stretched wire is \[U=\frac{1}{2}\times \text{stress}\,\text{ }\!\!\times\!\!\text{ }\,\text{strain}\] \[=\frac{1}{2}\times F\times x=\frac{1}{2}Fx\]


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