BCECE Engineering BCECE Engineering Solved Paper-2005

  • question_answer
    \[(\vec{a}+\vec{b}).(\vec{a}-\vec{b})=0\]implies that:

    A) \[\vec{a}=-\vec{b}\]                            

    B)  \[\vec{a}\ne \vec{b}\]       

    C)         \[|\vec{a}|=|\vec{b}|\]    

    D)         \[\vec{a}=\vec{b}\]

    Correct Answer: C

    Solution :

    \[(\vec{a}+\vec{b}).(\vec{a}-\vec{b})=0\] \[\Rightarrow \]\[\vec{a}.\vec{a}-\vec{a}.\vec{b}+\vec{b}.\vec{a}-\vec{b}.\vec{b}=0\] \[\Rightarrow \]    \[|\vec{a}{{|}^{2}}-|\vec{b}{{|}^{2}}=0\] \[\Rightarrow \]    \[|\vec{a}{{|}^{2}}=|\vec{b}{{|}^{2}}\] \[\Rightarrow \]    \[|\vec{a}|=|\vec{b}|\]


You need to login to perform this action.
You will be redirected in 3 sec spinner