A) \[{{C}_{2}}{{H}_{5}}Br\]
B) \[(C{{H}_{2}}){{(COOH)}_{2}}\]
C) \[{{(CH)}_{2}}{{(COOH)}_{2}}\]
D) \[{{C}_{2}}{{H}_{6}}\]
Correct Answer: C
Solution :
Key Idea: The compounds must fulfill two conditions to show geometrical isomerism. (i) The compound should have at least one \[C=C.\] (ii) The two groups attached to same carbon atom must be different. Out of given choices only (c) fulfills both conditions and shows geometrical isomerism. \[\underset{2-butene\,1,4-dioic\,acid}{\mathop{\underset{(c)}{\mathop{\underset{H-C-COOH}{\mathop{\underset{||}{\mathop{H-C-COOH}}\,}}\,}}\,}}\,\]
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