A) \[6.0\times {{10}^{23}}\]
B) \[3\times {{10}^{23}}\]
C) \[12\times {{10}^{23}}\]
D) \[3\times {{10}^{10}}\]
Correct Answer: A
Solution :
Key Idea: 1 mole= molecular mass in gram \[=6.02\times {{10}^{23}}\]molecules Given mass of \[C{{O}_{2}}=44g\] Molecular mass of\[~C{{O}_{2}}=12+16\times 2=44\] \[\therefore \] No. of molecules in 44 g of \[C{{O}_{2}}=6.02\times {{10}^{23}}\]
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