question_answer

The figure shows a network of currents. The magnitude of current is shown here. The current \[I\] will be:

A)  3 A                                        

B)         9 A

C)         13 A                                     

D)         19 A

Correct Answer: C

Solution :

Regarding Kirchhoffs junction rule, the circuit can be redrawn as: Current in arm,\[~AB=10-6=4A\] Current in arm, \[DC=6+2=8A\] Current in arm, \[BC=4+1=5A\] Hence,     \[I=5+8=13A\]