BCECE Engineering BCECE Engineering Solved Paper-2005

  • question_answer
    The surface tension of a liquid is 5 N/m. If a film is held on a ring of area \[0.02\,\,{{m}^{2}},\] its total surface energy is about:

    A)  \[\text{2 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-2}}}\text{J}\]                           

    B)         \[\text{2}\text{.5 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-2}}}\text{J}\]

    C)         \[\text{2 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-1}}}\text{J}\]                           

    D)         \[\text{3 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{-1}}}\text{J}\]

    Correct Answer: C

    Solution :

    Surface energy is related to the surface tension by the relation \[U=Td\,A\] Given,                   \[T=5\,N/m\]                 \[dA=2A=2\times 0.02=0.04\,{{m}^{2}}\] \[\therefore \]  \[U=5\times 0.04\] \[=0.20\,J\]         \[=2\times {{10}^{-1}}\,J\]


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