A) \[C{{H}_{3}}OH\]
B) \[{{C}_{2}}{{H}_{5}}OH\]
C) \[C{{H}_{3}}C{{H}_{2}}COOH\]
D) \[{{(C{{H}_{3}})}_{2}}CHOH\]
Correct Answer: A
Solution :
Key Idea: Methyl alcohol \[(C{{H}_{3}}OH)\]is prepared bypassing \[{{\text{H}}_{\text{2}}}\]in water gas in presence of catalyst \[\text{Co}\,\text{+}\,{{\text{H}}_{2}}+{{\text{H}}_{2}}\xrightarrow[300-400{{\,}^{o}}C]{C{{r}_{2}}{{O}_{3}}-ZnO}\underset{\text{methyl}\,\,\text{alcohol}}{\mathop{C{{H}_{3}}OH}}\,\]
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