BCECE Engineering BCECE Engineering Solved Paper-2004

  • question_answer
    \[C{{H}_{3}}C{{H}_{2}}OH\]convert into \[C{{H}_{3}}CHO\]in the presence of:

    A) \[N{{a}_{2}}C{{r}_{2}}{{O}_{7}}\]and \[NaOH\]

    B) \[N{{a}_{2}}C{{r}_{2}}{{O}_{7}}\]and dil. \[{{H}_{2}}S{{O}_{4}}\]

    C) \[NaOH\]

    D) Fe in presence of \[\text{NaOH}\]

    Correct Answer: B

    Solution :

    Key Idea: \[{{1}^{o}}\]alcohol are converted into aldehyde by reaction with \[N{{a}_{2}}C{{r}_{2}}{{O}_{7}}\]and \[{{H}_{2}}S{{O}_{4}}\] \[\underset{\text{ethyl}\,\text{alcohol}\,}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,+[O]\xrightarrow{N{{a}_{2}}C{{r}_{2}}{{O}_{7}}+{{H}_{2}}S{{O}_{4}}}\] \[\underset{\text{ethanal}}{\mathop{C{{H}_{3}}CHO}}\,\,+\,{{H}_{2}}O\]         


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