A) \[\text{0}\text{.27 }\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[\text{1}\text{.27 }\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[\text{2}\text{.12 }\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[\text{3}\text{.12 }\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: C
Solution :
Key Idea: Radius of nth orbit of hydrogen atom \[=0.529\text{ }{{n}^{2}}\] where \[n=\]no. of orbit \[=2\] \[\therefore \] \[{{r}_{2}}=0.529\times {{(2)}^{2}}=2.116\overset{\text{o}}{\mathop{\text{A}}}\,=2.12\overset{\text{o}}{\mathop{\text{A}}}\,\]
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