BCECE Engineering BCECE Engineering Solved Paper-2004

  • question_answer
    The heat produced by a 100 W heater in 2 min will be equal to:

    A)  \[\text{12 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{3}}}\text{J}\]                          

    B)         \[\text{10 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{3}}}\text{J}\]

    C)         \[\text{6 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{3}}}\text{J}\]                             

    D)         \[\text{3 }\!\!\times\!\!\text{ 1}{{\text{0}}^{\text{3}}}\text{J}\]

    Correct Answer: A

    Solution :

    Heat produced by heater is given by            \[H=Pt\] Given,\[p=100W,\,t=2\min =2\times 60\,s=120\,s\] \[\therefore \]  \[H=100\times 120=12\times {{10}^{3}}\,J.\]


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