A) 550 m
B) 137.5 m
C) 412.5 m
D) 175 m
Correct Answer: C
Solution :
Since, the object accelerates from rest, its initial velocity \[(u)\] is zero. That is, \[u=0\] From first equation of motion \[v=u+at\] \[\therefore \] \[27.5=0+a\times 10\] or \[a=2.75\,m/{{s}^{2}}\] Hence, distance covered in first 10 s \[{{s}_{1}}=ut+\frac{1}{2}a{{t}^{2}}\] \[=0+\frac{1}{2}\times 2.75\times {{(10)}^{2}}\] \[=137.5\,m\] Distance covered in next 10 s with uniform velocity of 27.5 m/s \[{{s}_{2}}=27.5\times 10=275\,m\] Total distance covered \[s=137.5+275=412.\text{ }5m\]
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