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BCECE Engineering BCECE Engineering Solved Paper-2003

  • question_answer
    If \[y=f(x)=\frac{x+2}{x-1},\] then \[x\] is equal to:

    A) \[f(y)\]                

    B)                   \[2f(y)\]

    C)                   \[\frac{1}{f(y)}\]                             

    D)                   none of these

    Correct Answer: A

    Solution :

    We have,   \[y=f(x)=\frac{x+2}{x-1}\] \[\Rightarrow \]               \[y(x-1)=x+2\] \[\Rightarrow \]               \[x(y-1)=2+y\] \[\Rightarrow \]               \[x=\frac{2+y}{y-1}\] \[\Rightarrow \]               \[x=f(y)\]


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