BCECE Engineering BCECE Engineering Solved Paper-2003

  • question_answer
    The temperature of cold, hot junction of a thermocouple are \[0{}^\circ C\] and \[T{}^\circ C\] respectively. The thermo-emf produced is\[E=AT-\frac{1}{2}B{{T}^{2}}.\]If A = 16, B = 0.08, the temperature of inversion will be:

    A) \[100{}^\circ C\]                              

    B)        \[300{}^\circ C\]

    C)        \[400{}^\circ C\]                              

    D)        \[500{}^\circ C\]

    Correct Answer: C

    Solution :

    Key Idea: At the temperature of inversion, the thermo emf is zero. Let temperature of cold junction be \[0{{\,}^{o}}C\]and that of hot junction be \[T{{\,}^{o}}C.\]The relation for thermo emf is given by \[E=AT-\frac{1}{2}B{{T}^{2}}\]                 Given,                   \[A=16,\,\,B=0.08\]                 \[\therefore \]  \[E=16T-\frac{1}{2}\times 0.08\times {{T}^{2}}\] Since, at temperature of inversion emf is zero, we have \[0=16\,T-0.04\,{{T}^{2}}\] \[\Rightarrow \]               \[T=\frac{16}{0.04}=400{{\,}^{o}}C\]


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