A) \[\Delta iC=245\,\mu A,\]\[\Delta {{i}_{E}}=250\,\mu A\]
B) \[\Delta {{i}_{C}}=252\,\mu A,\,\]\[\,\Delta {{i}_{E}}=145\mu A\]
C) \[\Delta {{i}_{C}}=125\,\mu A,\,\]\[\Delta {{i}_{E}}=250\mu A\]
D) \[\Delta {{i}_{C}}=252\,\mu A,\]\[\Delta {{i}_{E}}=230\mu A\]
Correct Answer: A
Solution :
Current gain in common emitter mode of transistor \[\beta =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{B}}}\] or \[\Delta {{i}_{C}}=\beta \Delta {{i}_{B}}\] Given, \[\beta =49\Delta {{i}_{B}}=5.0\mu A\] \[\Delta {{i}_{C}}=49\times 5.0=245\mu A\] For a transistor, emitter current is the sum of base current and collector current. i.e., \[{{i}_{E}}={{i}_{C}}+{{i}_{B}}\] \[\Rightarrow \] \[\Delta {{i}_{E}}=\Delta {{i}_{C}}+\Delta {{i}_{B}}\] \[\therefore \] \[\Delta {{i}_{E}}=245+5.0=250\mu A\]
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