BCECE Engineering BCECE Engineering Solved Paper-2003

  • question_answer
    If there is change of angular momentum from J to 5 J in 5 s, then the torque is:

    A) \[\frac{\text{3J}}{\text{5}}\]                                      

    B)        \[\frac{\text{4J}}{\text{5}}\]

    C)        \[\frac{\text{5J}}{4}\]                                   

    D)         None of these

    Correct Answer: B

    Solution :

    Key Idea: Torque is defined as rate of change of angular momentum. We know that rate of change of angular momentum (J) of a body is equal to the external torque \[(\tau )\] acting upon the body. i.e.,        \[\frac{dJ}{dt}=\tau \] Given,   \[{{J}_{1}}=J,\,{{J}_{2}}=5J\] \[\therefore \]  \[\Delta J={{J}_{2}}-{{J}_{1}}=5J-J=4J\] Hence,  \[\tau =\frac{4}{5}J\]     


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