A) 95th
B) 100th
C) 102th
D) 101th
Correct Answer: B
Solution :
Key Idea: If the difference of the consecutive terms is constant, then the series is in AP. Given series is \[3\text{ }+\text{ }8\text{ }+\text{ }13\text{ }+\text{ }18\text{ }+....+\text{ }498\] Here, \[a=3,\,d=5,\,\,l=498\] As we know \[{{t}_{n}}=l=a+(n-1)d\] \[\Rightarrow \] \[498=3+(n-1)\,5\] \[\Rightarrow \] \[(n-1)=\frac{495}{5}\] \[\Rightarrow \] \[n-1=99\Rightarrow n=100\]
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