BCECE Engineering BCECE Engineering Solved Paper-2002

  • question_answer
    Re \[{{\left( \frac{1+i}{3-i} \right)}^{2}}\] is equal to:

    A) \[-1/5\]                               

    B) \[~1/5\]                              

    C) \[~1/10\]            

    D)        \[~-1/10\]

    Correct Answer: A

    Solution :

    \[\operatorname{Re}\left[ \frac{{{(1+i)}^{2}}}{3-i} \right]\] \[=\operatorname{Re}\left[ \left( \frac{2i}{3-i} \right)\times \left( \frac{3+i}{3+i} \right) \right]\] \[=\operatorname{Re}\left[ \frac{6i-2}{9+1} \right]\] \[=\operatorname{Re}\left[ -\frac{2}{10}+\frac{6}{10}i \right]\] \[=-\frac{1}{5}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner