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BCECE Engineering BCECE Engineering Solved Paper-2002

  • question_answer
    The energy of an electron in the first Bohr  orbit is \[-\text{13}\text{.6 eV,}\] then find the energy of \[\text{H}{{\text{e}}^{\text{+}}}\]in the  same Bohr orbit:

    A) \[27.2\,eV\]                      

    B) \[-27.2\,\,eV\] 

    C)        \[54.4\,eV\]      

    D)        \[54.4\,eV\]

    Correct Answer: D

    Solution :

    Key Idea:  Energy of electron in H like ions\[=-13.6\times {{Z}^{2}}eV\] For He \[\,Z=2\] \[\therefore \]E of electron in \[H{{e}^{+}}=-13.6\times {{(2)}^{2}}\]                                                                 \[=-54.4\,eV\]


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