2. Solved Papers
  3. BCECE Engineering

BCECE Engineering BCECE Engineering Solved Paper-2002

  • question_answer
    The enthalpy and entropy change for a reaction is \[-2.\text{ }5\times {{10}^{3}}\,\text{cal}\] cat and \[7.4\text{ cal de}{{\text{g}}^{-1}}\]respectively. At 298 K the reaction is:

    A) reversible                           

    B) irreversible                                        

    C) spontaneous                    

    D) non-spontaneous

    Correct Answer: C

    Solution :

    Key Idea Any reaction is spontaneous when \[\Delta G\]is negative Given    \[\Delta H=-2.5\times {{10}^{3}}\,\text{cal}\]                                 \[\Delta S=7.4\,\text{cal}\,\text{de}{{\text{g}}^{-1}}\]                                 T = 298 K \[\Delta G=\Delta H-T\Delta S\]                 \[=(-2.5\times {{10}^{3}})-(298\times 7.4)\]                 \[=-2500-2205\] \[=-4705\,\text{cal}\] The reaction is spontaneous because \[\text{G}\]is negative.


You need to login to perform this action.
You will be redirected in 3 sec spinner