A) \[C{{H}_{3}}C{{H}_{2}}COOH\]
B) \[C{{H}_{3}}CHOHCOOH\]
C) \[HOOC.C{{H}_{2}}.COOH\]
D) \[C{{H}_{3}}.CO.COOH\]
Correct Answer: B
Solution :
Key Idea: Optically active compound has at least one asymmetric or chiral carbon atom (a)\[C{{H}_{3}}-\underset{H}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-COOH\] (b) \[C{{H}_{3}}-\underset{COOH}{\overset{H}{\mathop{^{*}\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-COOH\] (c) \[COOH-\underset{H}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-COOH\] \[C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-COOH\] Only choice (b) has asymmetric carbon atom (marked *) So it is optically active
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